lingo 出现1017min = 6*x11+2*x12+6*x13+7*x14+4*x21+9*x22+5*x23+3*x24+8*x31+8*x32+x33+5*x34;x11+x12+x13+x14=30;x21+x22+x23+x24=25;x31+x32+x33+x34=21;x11+x21+x31=15;x12+x22+x32=17;x13+x23+x33=22;x14+x24+x34=12;
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数学建模中,软件LINGO中同时出现min=x+y和min=y怎么办(也就是x和y之和最小的前提下,尽量让y最小)
lingo 出现1017min = 6*x11+2*x12+6*x13+7*x14+4*x21+9*x22+5*x23+3*x24+8*x31+8*x32+x33+5*x34;x11+x12+x13+x14=30;x21+x22+x23+x24=25;x31+x32+x33+x34=21;x11+x21+x31=15;x12+x22+x32=17;x13+x23+x33=22;x14+x24+x34=12;
为啥运行LINGO时会出现错误代码11,MODEL:SETS:CHSH/1..6/;LINKS(CHSH,CHSH)/1,2 1,3 2,3 2,4 3,5 4,3 4,6 5,4 5,6 6,1/:C,U,F;ENDSETSDATA:U=8,7,5,9,9,2,5,6,10,15;C=2,8,5,2,3,1,6,4,7,8;ENDDATDN= @SIZE(CHSH);F(6,1)=14;MIN= @MIN( LINKS(I,J)|I#LT#N:C
lingo中输入min=x;1312.5x-y7.79为什么老是显示unexpected jacobian o
lingo@min与@smin的区别
Lingo最优化问题用Lingo集合(循环)编程求解:min z=-x1^2-x2^2-x3^2-x4^2+x1+2*x2+3*x3+4*x4s.t. x1+x2+x3+x4>=2 x1.x2.x3.x4∈{-1,1}程序里必须出现@sum和@for
lingo矩阵怎样用lingo软件或者MATLAB写出规划问题解min=sum|x(i)-c(i)|*d(i)条件a(i)
请问这两个语句有什么区别啊?我正参加我们学校的数学建模,用lingo求解时出现了问题,1.min=@sum(assigin(i,j):d1(i,j)*(20*@abs(x1-a(i))+30*@abs(y1-b(j)))+d2(i,j)*(20*@abs(x2-a(i))+30*@abs(y2-b(j))));.2.min=@sum(assigin(i,j)
LINGO min 45;(x1+x2) ST x1+x2>=1 x1min 45;(x1+x2)STx1+x2>=1x1
lingo中min=sqrt(x^2+(y-a)^2)+sqrt((x-b)^2+(y-c)^2)+y;为啥不对
LINGO 错误1017min=7.2*(((x1^2+(y1-5)^2)^(1/2))+((x1-15)^2+(y1-y2)^2)^(1/2)+(25+(8-y2)^2)^(1/2)+x1)+21*(25+(8-y2)^2)^(1/2)STx1>0x10y1
用LINGO做题时出现未知数怎么做?
怎样用Lingo求解0-1规划模型 急用…大家帮忙谢啦…怎样用Lingo求解0-1规划模型急用…大家帮忙谢啦…min z=x1+x2+…+x18a=5*x1+5*x2+4*x3+…+x18+2>=201/6a
min Q=x+y+z x+y+z>=687 x+y+z>=983 x+y+z>=674 x+y+z>=918 x+y+z>=1206这个用lingo解出现小问题TOO MANY INEQUALITY OR EQUALITY RELATIONS?要怎么改才可以求出答案啊?
帮我看看这段lingo代码,我不明白为什么一直出现error code11的错误MODEL: SETS: QUARTERS/1,2,3,4/:DEM,RP,OP,INV; ENDSETS MIN=@sum{QUARTERS:400*RP(i)+450*OP+20*INV}; @FOR{QUARTERS{I}:RP{I}
求大神指点,lingo出现错误代码11,这是为什么?model:!目标函数;min=(0.005*((@log(1+k))^2+(@log(1+2*k))^2+(@log(1+3*k))^2+(@log(1+4*k))^2+(@log(1+5*k))^2))!/(@log(1+k)+@log(1+2*k)+@log(1+3*k)+@log(1+4*k)+@log(1+5*k));!约束条件;(@log
Lingo运行出现“Improper use of set name”,怎么修改?model:sets: num1/nl1/:i; num2/nz0..nz33/:j;endsets目标函数; min=@sum(num1(I):@sum(num2(J):num1(I)*Q-X0*((num1(I)-1)*t+num2(J))))*0.2+282*0.2+18*m*q+75*m+48000;约束条件; 3+(m-1)*
下面公式用lingo如何表示?z=max (d1,d2,d3,d4,d5);d1=min(2*x11+10*x21+9*x31+7*x41+8*x51+12*x61+5*x71);d2=min(15*x12+4*x22+14*x32+8*x42+4*x52+4*x62+16*x72);d3=min(13*x13+14*x23+16*x33+11*x43+15*x53+6*x63+8*x73);d4=min(1*x14+15*x24+13*x34+9*x44+8