1/xy-y∧2,x+y/x∧2-y∧2通分,
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/15 21:41:20
xKN0EEL`~c41M( #Fk` #1l'OJGWG5A|9h2]h:~?zNPS6;5U7vq4젊8+t|pVyHߢ'գGn8+z-1FoJdg Թ P5CZfh8́Qf
l!˵ H9%gGIXa1Z!*.byTW.]~nl°T
1/xy-y∧2,x+y/x∧2-y∧2通分,
.(x+y-2)(x+y-2xy)+(xy-1)^2
(x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1)
(-1/3xy)∧2*[3xy(2x-y)-3x(2xy-4y∧2)]
设x,y∈R,比较x∧2+y∧2+1与x+y+xy的大小?
已知x+y=6,xy=-3,则x∧y+xy∧2=
(-x-y)(x^2+xy+y^2)
化简x^-y^/x^-2xy+y^
2*(x-y)²(y-x)(xy)
1、(-7x^y)(2x^y-3xy^3+xy) 2、((x-y)^6)/((y-x)^3)/(x-y)
{(x-y/x^2-2xy+y^2)-(xy+y^2/x^2-y^2)}*(xy/y-1)
因式分解2x∧2-5xy+2y∧2+3x-3y+1
根号x+y-1+(xy+2)∧2=0,则X,Y的取值
X-Y/2X+2Y XY/X+Y²
(x/x+y-x/y-x-2xy/x.x-y.y)/(1/x-1/y) 分式化简
因式分解:x×x-xy-2y×y-x-y
因式分解 1-x∧2+2xy-y∧2
xy-x-y+1/y²-2y+1