设计X=-3,Y=2和X=6,Y=-4都是它的解的二元一次方程.并求当X=2时方程的解

当x=--y=---时3x+2y和5y-6x的值都等于-3 (2x-2y)/3-(x-y)=-1和6(x+y)-4(2x-y)=16 解方程组3(x+y)-4(x-y)=4和(x+y)/2+(x-y)/6=1kkkkkkkk 三个方程组,①x-y=3 ②2（x-y+1）=4（x+y）-6 3x-8y=14 x/2+y/4=-3③3（x+y）+2（x-y）=362(x+y)-3(x-y)=24每个方程组都需要过程和结果（只是结果也行） {3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1 x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20 {(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20 4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6 （x+y）/2- x-y/2=6 3(x+y)=4(x-y) x+y/3+x-y/2=6 4(x+y)-2(x-y)=40 (x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)= 设计一个二元一次方程,使{x=-3 y=2和{x=2 y=-3 x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 (x-2y)(x+y)-2x(-2x-3y)+6x(-x-y),其中x=-1,y=2要讲解和答题 【2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2】/2(x-y)^2= 已知X,Y,满足(X+3Y)(X-3Y)=-10(Y^2-6/5)和2X(Y-1)+4(1/2X-1)=0 （X+Y)^2 X^2Y+XY^2注：*/* 是分数 设计二元一次方程x=2 y=-3 2x+4y=3 -3x-2y=1 ..求x和y