10(y+z)^2-29(y+z)+10十字相乘因式分解如果可以的话 最好化出十字架不行就算了

10(y+z)(y+z)-29(y+z+10)分解因式 x/10=y/5=z/7 x+y+2z=29 求x y z X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z 解方程 Y=X+Z Y-Z=2 100Z+10Y+X-(100X+10Y+Z)=99 Y=X+ZY-Z=2100Z+10Y+X-(100X+10Y+Z)=99 x+2y+3z=23 y-z=5 x+2z=10 X=3z X+y+z=12 X+2y-2z=10 2x+z=10 x+y-z=4 3x-y-z=0 (4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=? (4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊 x-y-2z=10 y-3z=-4 3x-y+5Z=21 三元一次方求大神x-y-2z=10y-3z=-43x-y+5Z=21 x+2y+3z=10,x-y+4z=10,x+3y+2z=2 x+2y+3z=10,x-y+4z=10,x+3y+2z=2 解方程：｛3x-y-z=2,｛3y-x-z=-10,｛3z-x-y=10 {x+2y+3z=11,x-y+7z=10,x+3y+2z=2 x-y+4z=10,x+3y+2z=2,x+2y+3z=11. x+y+z=4 2x+3y-z=6 3x+2y+2z=10 ｛3x-2y+z=-1 2x+y-3z=10 x-y-2z=1 x+2y+3z=10,4x+3y+2z=15则x+y+z=