Main() {int x[][4]={1,2,3,4,5,6,7,8,3,9,10,2,4,2,9,6},s=0,k=0； for(；k

main(){ int x=5; while(x # include void main( ) { int x = 4 ; do { printf( %d ,x-- ) ; } while( x ) ; } #include main() { int x=0; while(x++ main(){int x,i;for(i=1;i #include int call(int s[],int y) { static int t=3; y=s[t--]; return(y); } void main() { in#includeint call(int s[],int y){static int t=3;y=s[t--];return(y);}void main(){int a[]={3,8,4,2},n,x=0;for(n=0;n #include int main(){ int x=0,y=0; while(x #include void main(){int k1=1;int k2=2;int k3=3;int x=15;if(!k1) x--;else if(k2) x=4;else x=3;printf(%d,x);} void main() {int x=4;if(x++>=5)printf(%d/n,x);else printf(%d/n,x--); 求高手解释一下这段程序#include class Test {int x,y; public: Test(int i,int j=0) {x=i;y=j;} int get(int i,int j) {return i+j;} }; void main() {Test t1(2),t2(4,6); int (Test::*p)(int,int=10); p=Test::get; cout C语言问题int x=3;incre();main(){ int i; for (i=1;i int x=3;main(){int i;for(i=1;i int x=3;main(){int i;for(i=1;i #include Int main(void ) { int a = 5,b = 4,x,y; x = 2 * a++ ; printf(a=%d,x=%d ,a, #include Int main(void ) { int a = 5,b = 4,x,y; x = 2 * a++ ; printf(a=%d,x=%d ,a, main(){int a[]={2,4,6,8,10};int y=1,x,*p;p=&a[1];for(x=0;x #define f(x) x*x main( ) { int i; i=f(4+4)/f(2+2); printf(%d ,i); } 以下程序输出的结果是 main() {int x; x=-3+4%6/5； printf（%d,x）； } int func(int x,int y ) { return(x+y) } main() {int a=1,b=2,c=3,d=4,e=5;printf(&d ,func((a+b,b+c,c+a),(d+e)));