x+y+z=18 8x+6y+6z=112 2y+z=22 这个方程怎么解?

解方程 x(x+y+z)=6 y(x+y+z)=12 z(x+y+z)=18 解方程组{x(x+y+z)=6,y(x+y+z)=12,z(x+y+z)=18 x/3=y/6=z/8 3x+5y-6z=-18 求x,y,z x+y+z=18,8x+6y+6z=118,2y+z=20求解过程 解方程组：{x(x+y+z)=6 {y(x+y+z)=9 {z(x+y+z)=10 ..1.x+y+z=26,2.4y+3z=7,y-z=1,3x+2z=17,x+2y-z=18 9x-7y=173.x-7y+3z=17 4.2x+4y+3z=95x-6y-z=24 3x-2y+5z=113x+7y-2z=1 5x-6y+7z=131.x+y+z=26,y-z=1x+2y-z=18 2.4y+3z=7,3x+2z=11,9x-7y=17 3.x-7y+3z=17 5x-6y-z=24 3x+7y-2z=14.2x+4y+3z=93x-2y+5z=11 5x-6y+7z=13 若x-y=6,xy=-8,求代数式(x+y+z)²+(x-y-z)(x-y+z)-2·z(x+y)的值 若x+y=6,xy=-8,求代数式(x+y-z)^2+(x+y-z)(x+y+z)-2·z(x-y) 已知x-y=6,xy=-8,求代数式½(x+y+z)²+½(x-y-z)(x-y+z)-z(x+y) (x+y-z)(x-y+z)= 已知x、y、z满足方程组：x+y-z=6；y+z-x=2；z+x-y=0 求x、y、z的值 已知X.Y.Z满足方程组,X+y-Z=6y+z-x=2z+x-y=0求X.Y.Z的值 x+y+z=6 x+2y+3z=14 y+1=z 2x+3y+z=11,x+y+z=6,3x-y-z=-2求解 2x+3y+z=11,3x+y-z=2,x+y+z=6求解 x+y+z=6,y+z+a=9,z+a+x=8,a+x+y=7 解方程组x-y-3z=4 3x+y-z=6 -x+3y+z=8 解方程组x-y-3z=4 3x+y-z=6 -x+3y+z=8