化简(tan5π/4+tan5π/12)/(1-tan5π/12)(tan 5π/4 + tan 5π/12)/(1-tan 5π/12) =(tan π/4 + tan π/6+π/4 )/(1-tan π/4*tan π/6+π/4 ) =tan(π/4 + π/6+π/4 )=tan(π/2+π/6) 请问我这样算错在哪呢?tan π/2不是无意义吗?

化简(tan5π/4+tan5π/12)/(1-tan5π/12) 化简(tan5π/4+tan5π/12)/(1-tan5π/12) 注意分母啊 细心! tan5分之π+tan5分之2π+tan5分之3π+tan5分之4π怎么算 sin(a+β)cos(r-β)-cos(β+a)sin(β-r)跟tan5π/4+tan5π/12 / 1-tan5π/12要怎么算 计算 tanπ/12-tan5π/12 （1－tan5π/12tanπ/4）/（tan5π/12＋tanπ/4）的值 数值：sin9π/4+cos2π/3+tan5π/4 数值：sin9π/4+cos2π/3+tan5π/4 比较大小:tanπ/5,√3,tan5π/12 求值cos2π/5*tan5π tan5/12多少度 化简(tan5π/4+tan5π/12)/(1-tan5π/12)(tan 5π/4 + tan 5π/12)/(1-tan 5π/12) =(tan π/4 + tan π/6+π/4 )/(1-tan π/4*tan π/6+π/4 ) =tan(π/4 + π/6+π/4 )=tan(π/2+π/6) 请问我这样算错在哪呢?tan π/2不是无意义吗? 求人教版数学必修四P137 13化简的（7）——（9）题 （7）sin(a+b)cos(γ-b)-cos(b+a)sin(b-γ)（8）sin(a-b)cos(b-γ)-cos(a-b)sin(γ-b)（9）tan5π/4+tan5π/12 / 1-tan5π/12 高中三角函数变换题化简：一、sin40°（tan10°-根号下3）二、1÷sin10°-根号下3÷cos10°三、tan20°+tan40°+根号下3tan20°tan10°四、（tan20°+tan40°+tan120°）÷tan20°tan40°五、（tan5π/4+tan5π/12）÷（1-tan5π sin9π/4+cos2π/3+tan5π/4的值. sin4π/3×cos25π/6×tan5π/4的值是 sin4π/3 * cos25π/6 * tan5π/4的值是? sin4π 点乘 cos25π/6 点乘 tan5π/4的值是