若关于x的方程:x²-(k+2)x+2k-1=0的两个实数根分别为x1,x2,且x1²+x2²=11,求k的值.马虎同学是这样做的:∵x1+x2=k+2,x1x2=2k-1,x1²+x2²=11∴由x1²+x2²=(x1+x2)²-2x1x2得(k+2)²-

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