(x^2+ax+5)(x^3+2x+3)的展开式中不含x^2的项,则a的值是什么?

2x²-5x-ax+3a-3 因式分解 分解因式：2x^3+x-3还有x^2+2x-15-ax-5a 若多项式2x*x*x*x-3x*x*x+ax*x+7x+b能被x*x+x-2整除,求a:b 因式分解：①2ax^2-11ax+5x ②3x^3+3x^2-18x *-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || 函数f(x)=(x2+2x-3)/(x-1) (x>1) ax+1 (x 填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x 因式分解 x^3+2x^2-16x-32和x^3+ax^2-2X^2-2ax 已知（ax^2+x-b)(ax^2-x+b)-ax(ax^3+x-1)的化简结果中不含x^2项和x项,求b^a {x|ax²+ax-3 (7-2x+x^2)-(5+3x-2x^2)=-(x^3+2x^2-1)+(x^3-2x^2+x-2)=(2ax-3by-5)-2(ax-2)+(-2by+1)= x^2+2ax+1,x∈[3,5]求f(x)的值域如题 合并同类项:5a-3x+4a+8x-5ax-2x 如果关于x的不等式ax-a>3x+5的解和-2x 求使不等式ax*x-2x+1>ax*x-3x+5(a>0,且不等于1）成立的X的集合 (x+1)(x+2)(x+3)(x+4)(x+5)(x+6)(x+7)(x+8)(x+9)(x+10)请化简我说的是化简化成x^10+ax^9+bx^8+cx^7+......+n的形式 因式分解：x^3+6x^3+11x+6 6x^4+5x^3+3x^2-3x-2 x^4-11x^2+1 2x^3-ax^2-5a^2x-2a^3x^3+6x^2+11x+66x^4+5x^3+3x^2-3x-2x^4-11x^2+12x^3-ax^2-5a^2x-2a^3 A={x|x^3+3x^2+2x>0} B={x|x^2+ax+b