log2 56-log2 7怎么算来着?
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log2 56-log2 7怎么算来着?
求值:log2 (5/56)^(1/2)+log2 (14)-(1/2)log2 (35)=log2中2为底数=1/2[-2log2 (7)-3]+log2 (2)+log2 (7) 中的1/2[-2log2 (7)-3]是怎么得到的?
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