设A={(x,y)|x^2+(y-1)^2=1},B={(x,y)|x+y+m>=0},则使A是B子集成立的实数m的取值范围是我的想法是,直线与圆相切 用距离公式 不知可否
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设A={(x,y)/x+y
设y(x)=(1+x^3)(5-1/x^2),求y'(1),y'(a).把步骤写清,跪拜设y(x)=(1+x^3)(5-(1/x^2)),求y'(1),y'(a).
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