1、已知x^2+y^2+6x-4y+13=0,则(x+y)^2006的值为_____.2、若x^2-x+1=0,则x^2001=______.3、若a为有理数,且x=2004a+2003,y=2004a+2004,z=2004a+2005.求x^2+y^2+z^2-xy-yz-zx的值.4.分解因式:-4m^3+16m^2-12m
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