x+1∕5+1=y-1∕2与3x+4y=32的方程组解怎么结果都不一样啊。

化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1 {3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1 (x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5) 已知y=y₁+y₂,y₁与x成正比例,y₂与x-1成正比例,且x=3时y=4；x=1时y=2,求y与x之 请问 0=-5x+y-1 与 1=4x-3y+2 x*y的值是多少 x+y+2(-x-y+1)=3(1-y-x)-4-(y+x-1),x+y=? {(x+y)/2+(x-y)/3=1,(x+y)-5(x-y)=2.求x=?,y=? 已知（3x-2y+1)的平方与/4x-3y-3/无为相反数,则x=___,y=___ 3x+2y/4=2x+y/5=x-y+1 {x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0 2x-y=8 3x+2y=5与3x+2y=1 3x-4y=-11用加减法怎么算? 2x-5+y/3=x+3y/4+7与10(x-y)-4(1-x)/3-y=0 求方程组的解 已知4份之3x+2y=6份x-y+1=5份之2x+y,求x与y的值 3x-2y=1 4x-5y 先化简 再求值 (2x-y)(y+x)-(x-2y)(2y+x)-(-3y+x)^2其(√x+1)+y^2+4=-4y 已知x-y=1,求[(x+2y)^2+(2x+y)(x-4y)-3(x+y)(x-y)]除以y的值大神们帮帮忙 已知x-y=1,求[(x+2y)²+(2x+y)(x-4y)-3(x+y)(x-y)]÷y的值 (x-y)/4+(x+y)/5=1/4 (x+y)/9-(x-y)/3=//2(x-y)/4+(x+y)/5=1/4(x+y)/9-(x-y)/3=//2 初二数学多项式乘多项式计算题与不等式①(2x-3)(x-4)-2(x-1)(2+3x)-(2x-5)(x+3)②（3x-2）(2x+3)-6x(x-1)≤2（x-2）③（2x-y)（2x+y)+（x+y)（x-2y）④先化简,再求值,(y-3)(4-5y+2y²)-2y(y²-8y+2),其中y=1