若有x = 1,y = 2,z = 3,则表达式（x < y x :y）= = z++的值是多少

若|x+3|+|y-2|+|2×z+1|=0求(x×z-y×z)(y-x+z)的值 若x+y+z=3y=2z,则x/x+y+z=? 若x:y:z=3:2:1,则x+2y-z/2x-y+z= 若xyz=1,求证 x^2/(y+z)+y^2/(z+x)+z^2/(x+y)≥3/2 x+y+z=6 x+2y+3z=14 y+1=z 已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值 已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值 急 x,y,z均为正整数,x>=y,y>=z,z>=8 x+3y-z=急x,y,z均为正整数,x>=y,y>=z,z>=8x+3y-z=132,请问1.x+y+z有最小值782.x+y+z有最大值1343.洽有一组解(x,y,z)使得x+y+z有最大值4.x+3y有最小值1405.x+2y有最大值130 已知x:：y：z=3：4：5,(1)求x+y分之z的值；（2）若x+y+z=6,求x,y,z. 已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 求解一道数学题若x+y+z+3=2(根号x+根号y+1+根号z-1),求（x+y+z)的（y-z）次方 若x+y+z+3=2(根号x+根号y+1+根号z-1）求（x+y+z）y-z 已知X Y Z都是非负数,且满足X+2Y-Z=1,2X+3Y-3Z=1,若有P=X+Y+Z,试求P的最大值和最小值 若X、Y、Z满足2/(x-1)=3/(y+1)=4/(z-2),求X、Y、Z为何值时,x^2+y^2-z^2有最大值?并求出这个最大值. matlab解对数方程组[x,y,z]=solve('0.29744*x/(3+0.1*x+y+z)=(log10((3+x+y+z)/(3+0.1*x+y+z)))^2','0.79*x/(3+0.1*y+z)=(log10((3+x+y+z)/(3+0.1*x+y+z)*(3+y+z)/(3+0.1*y+z)))^2','1.25*x/(3+0.1*z)=(log10((3+x+y+z)/(3+0.1*x+y+z)*(3+y+z)/(3+0.*1y+z)*(3+z)/ {x+y+z=1;x+3y+7z=-1;z+5y+8z=-2 如果,根号x-3+| y-2 |+z^2=2z-1 求 （x+z)^y