若(x+2)-(x+1)/(x+1)(x-2)=a/x+1-b/x+2,其中a,b为常数,则ab=___
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分解因式----(X*X-X)(X*X-X-2)+1
】x(x+1)+x^2(x-1)
1/(1-x)+1/(1+x)+2/(1+x*x)+4/(1+x*x*x*x)+8/(1-x*x*x*x*x*x*x*x)怎么做
x/x+(1-x)/x-1/x
若x∈【-1,2】,x*3-x*2-x
x-1/x-2
{2X+1}+{X}
(x^2-1)/x
x^2-1/x
2X+|X+1|
|x-1|+|x-2|
(x+1)/(x+2)
/X+1/+/X+2/
2x/(1-x)
|X+2|+|X-1|