消元法4x-3y=14,5x+3y=31
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/22 09:12:43
xN@_%gMc8U.Hb(4Q"6]*Q(ji"6}]^HU7սG̙^+X͇ ~_}QDDޔ[ZyAÐT/BW+Cv;x$˴f
6٫Z4}F[z ȡA<#¦(֡ФG=0#2v=]gkc9Θi6}Vm3O3x?9Dŧ"J]D!/:
¢"eRSrz{Ó|+7(q 5*wD0Zs|^?]4eʴ;gi7Kh6ޟ_-fni_
|t:zV
(x+y-5)*(x+y-5)+(x-y+3)=0 x*x-y*y
已知:3x-5y=0,求x/y,x-y/y,x-y/x
6(x-y)-2(x+y)=14 3(x-y)+(x+y)=5
(5x+3y)(3y-5x)-(4x-y)(4y+x)=
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2
先化简再求值(x-y)(x-2y)+(x-2y)(x-3y)-2(x-3y)(x-4y) x=4 y=5
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
4x-2*(10-x)-10=5y-3*(10-y)x+y=14
消元法4x-3y=14,5x+3y=31
用加减消元法解下列方程组:(1)4x-3y=14,5x+3y=31(2)2x-5y=-21,4x+3y=23(3)4x+7y=-19,4x-5y=17(4)3(x-1)=y+5,5(y-1)=3(x+5)
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
1:4(x-100)+3y=5 2:6(x-y)-2(x+y )=14 x-100=-y 3(x-y)+(x+y)=5 先无视上面的1.4(x-100)+3y=5x-100=-y2.6(x-y)-2(x+y )=143(x-y)+(x+y)=5
若(-x+6):(x-y):(4x+y)=3:14:1,求x+y
若(-x+6):(x-y):(4x+y)=3:14:1,求x+y