sin(-11兀/6)+cos13兀/3×tan4兀
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sin(-11兀/6)+cos13兀/3×tan4兀
cos13兀/6
求值sin(-23/6 π)+cos13/7 πtan4π-cos13/3π
计算:sin(-23π/6)+cos13π/7*tan4π-cos13π/3
三角代数式sin(-23/6∏)+cos13/7∏乘tan3∏-cos13/3∏的值为
计算sin7π/3cos13π/6+sin(-11π/6)cos(-11π/3)
sin(-4π/3)= cos(-79π/6)= cos13π/6=
1.化简:(sin450°-α)-sin(180°-α)+cos(450°-α)+cos(180°-α)的值2.化简:sin(-23/6π)+cos13π/7xtan4π-cos13/3π
与cos13π/3的值相同的是 :A.nπ/3 B.sinπ/4 C.sinπ/6
求值sin7π/3cos(-23π/6)+tan(-11π/4)cos13π/3
COS13/6π
计算:cos13π/4+tan(-11π/6)=?
计算:√3sin(-20/3∏)-cos13/4π×tan(-37/4π)
1、sin347 cos148+cos13 cos58等于()2、已知tanα=3,则sinα-2sinαcosα+3cosα等于()3、计算5sin90+2cos0-3tan180+6cos180(要过程)
将下列三角函数转化为锐角三角函数(1)COS13/9π= (2)SIN(1+π)= (3)SIN(-π/5)= (4)COS(-70°6′)=
将下列三角函数转换为锐角三角函数1)COS13/9 π 2)SIN(1+π) 3)sin(-π/5) 4)cos(-70度6分) 求详细解答方法
计算不太明白...求值sin(-1320°)*cos1110°+cos(-1020°)sin750°+tan(-405°)求值sin25π/6+cos25π/3+tan25π/4+sin7π/3*cos13π/6-cos5π/3
sin13π/6+cos13π/3-tan(-23π/4)=