(1/4x^4y^3-1/2x^4Y^5-1/6X^3Y^2)/(-1/2x^3y^2 )=?不好意思啊,发错题了.是除以(-1/2x^3y^2)
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/04 22:50:50
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化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
x²/xy-x/y 3x/4x+y - x-2y/4x+y (1-y/y+x)÷x/y²-x²
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
(x+y)(x-y)+4(y-1)
x+y+2(-x-y+1)=3(1-y-x)-4-(y+x-1),x+y=?
{x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0
-5(x-2y+1)-(1-3x+4y)
3x-2y=1 4x-5y
(x-y)/4+(x+y)/5=1/4 (x+y)/9-(x-y)/3=//2(x-y)/4+(x+y)/5=1/4(x+y)/9-(x-y)/3=//2
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因式分解(x-2y)(x-3y)+(x-4y)(x-5y)+(x-3y)(x-5y)+(x-2y)(x-4y)
计算:1/(x-y)-1/(x+y)-2y/(x^2+y^2)-4y^3/(x^4+y^4)-8x^7/(x^8+y^8)
先化简 再求值 (2x-y)(y+x)-(x-2y)(2y+x)-(-3y+x)^2其(√x+1)+y^2+4=-4y
已知x-y=1,求[(x+2y)^2+(2x+y)(x-4y)-3(x+y)(x-y)]除以y的值大神们帮帮忙
已知x-y=1,求[(x+2y)²+(2x+y)(x-4y)-3(x+y)(x-y)]÷y的值
-(5x+y)-7(x-y) -2分之1(x+y)+4分之1(x+2y) 4x-2(x-2) -2x-(3x-1) x-(5x-2y)+2(2x-y)
1/(x-y)+1/(x+y)+2x/(x^2+y^2)+4x^3/(x^4+y^4)化简
x²-y²+5x+3y+4(x+y-2xy)(x+y-z)+(xy-1)²