3t^2+3t-1-t^3=0,

3t^2+3t-1-t^3=0, 3t+t-2t=? 已知f(t)=3t*t-2t-2/t+3/t*t,证明f(t)=f(1/t) 4t^-8t+5-3t^+6t-2 其中t=2/1 求(1+t)*(27t+3)/((1+3t)^2)的最大值 t〉=0 4t^3-3t^2-2t+1=0 t等于多少 （t*t）-4t+3=0求t (2t+3)(2t-)-(4t+1)(t-9) [T,Y]=ode45(@rigid,[0 1],[rand(15,1)]);plot(T,Y(:,1),'-',T,Y(:,2),'-.',T,Y(:,3),'.',T,Y(:,4),'-',T,Y(:,5),'-.',T,Y(:,6),'.',T,Y(:,7),'-',T,Y(:,8),'-.',T,Y(:,9),'.',T,Y(:,10),'-',T,Y(:,11),'-.',T,Y(:,12),'-.',T,Y(:,13),'.',T,Y(:,14),'-',T,Y(:,15),'.') 化简t+1/t-(t+2)²-1/t²×t+1/t+3 (t^5+t^4+t^3+t^2+t+1)(t-1) 用直式计算 t（t-2）-3t=0 解方程t（t-2）-3t =0 5t平方-2t+3=0求t 79.788456t - 1250t^2 - 8311.297508t^3 = 1 当t=1时,代数式t^3-2t[2t^2-3t(2t+2)]的值 3t^2-1=6t 下面程序为何在matlab中运行不了啊?t=1:80C(t)=-3.22*t^3+386.8*t^2-5500.912*tSi(t)=773.6*t-9.670*t^2;So(t)=5500.912;t=81:150C(t)=-275.456*t^2+61885260;Si(t)=0;So(t)=5500.912plot(t,C(t))plot(t,Si(t),t,Si(t),'r')