求下列各式的值⒈ (3x^4-2x^3)÷(-x)-(x-x^2)·3x,其中x=-1/2⒉ [(ab+1)(ab-2)-2a^2b^2+2]÷(-ab),其中a=3/2,b=-4/3已知(x+y)^2=1,(x-y)^2=49,求x^2+y^2与xy的值已知a=b=3,ab=2,求a6^2=b6^2
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