一直数列an满足:a1=1/2,3(1+a n+1)/1-an=2(1+an)/1-a n+1,ana n+1/1),数列bn满足bn=（a n+1）^2(n>/1) (1)求an bn通项公式 （2）证：数列bn中任意三项不可能成等差数列

数列｛an｝满足a1=1,且an=an-1+3n-2,求an 一直数列{An}满足A1=1/2,A1+A2+…+An=n^2An用数学归纳法证明An=1/[n(n+1)] 数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an 已知数列{an}满足a1=1/2,an+1=3an+1,求数列{an}通项公式 数列an满足a1=1/2 an+1=an/(2an+3) 猜想数列通项公式 数列{an}满足a1=a,an+1=1+1/an.若3/2 数列an满足a1=1/3,Sn=n(2n-1)an,求an 数列[An]满足a1=2,a（n+1）=3an-2 求an 已知数列{an}满足a1=1 an+1=an/(3an+1) 则球an 数列a1=3,数列满足2an=Sn乘以S(n-1),求通项公式. 已知数列an满足 a1=1/2,an+1=3an/an+3求证1/an为等差数列已知数列an满足 a1=1/2,an+1=3an/an+3求证1/an为等差数列 设数列AN满足A1等于1,3(A1+a2+~+AN)=(n+2)an,求通向公式 若数列{An},满足关系a1=2,an+1=3an+2,求数列的通项公式 若数列【an】满足a1等于1,An+1=2an+3n,则数列的项A5 已知数列{an}满足:a1=3,an=Sn-1+2n,求数列an及sn 已知数列{an}满足a1=1,a2=3,an+2=3an+1-2an求an 1.一直{an}中,a1=1,an+1/an=1/2,则数列的通项公式为?2.已知数列{an}满足a1>0,且an+1=（n/n+1）*an,则数列{an}是一个怎么样的数列（递增?递减?常数列?摆动数列?）3.数列的项数是无限的吗? 数列｛an｝满足a1=3,a n+1=2an,则a4等于