函数f(x)的解析式为f(x)=sin(2x+π/3)-根号3sin²x+sinxcosx+根号3/2若当x∈[π/12,7π/12]时,f(x)的反函数为f//(x),求f//(1)的值.化简出来是2sin(2x+π/3)
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