设函数f(x)=sin(2x+φ)(-π＜φ＜0）,y=f(x)图像的一条对称轴是直线x=π/8.(1)求φ; （2）画出函数f(x)（2）画出函数f(x)在区间[0,π]上的图像.

来源：学生作业帮助网 编辑：作业帮 时间：2024/10/02 21:25:50
xՓAn@E*JDǓ8q6p gl׆61uUP@Y ZPH q_"3.\qB"lP=G4ϽkW5n Ga`+:k+ {t÷9։U`;]V<q_ 5v K(.QRLLB X+c$$&R-\ [EDY(K5uRPT#"0 \̒?eHHNj7ePPRdq˥ 5
设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(0 设函数 f(x)=sin(2x+y),(-π 设函数f(x)=sin(wx+t)(-π/2 设函数f(x)=sin(wx+t)(-π/2 设函数f(x)=sin(2x+φ）（-π 设函数f（x）=sin（2x+φ）（-π 设函数f(x)=sin (2x+φ）,（-π