已知{an}为等比数列,a1=1,a5=256,S n为等差数列{bn}的前n项和,b1=2,5S5=2S8 设Tn=a1b1+a2b2+...+anbn,求Tn

来源:学生作业帮助网 编辑:作业帮 时间:2024/09/18 15:34:31
xV[OG+#Uv=ݥNxCZ#>Fhn4RZR.% &uy?kx/;s16Kҕ;soΞۜىӭۙm\(d"A2 &2ѮY]Swzkqx1T$v{2LdM Sj]\_Q>lnv+vvy{-KPQIH #RPilLuoJuT(~?hvz\(aN+4hL$cf7$5㪓UhWz**5,XMThL{muY[/5{IF'<^<}kqkSutdk6, b+/WC6\_iXseh0:sC|O23}xxg3?[o>wFDЀt̝q5V *bhUX!d9sLLMד>37ai:a0@Zӫq9HBMTzJw4 XFS߿Vw1`4sI;W}yV؀ba?>0_@(KI׈N$.BA1ѵ `!-"3PH &Gj#Zy#3ıGVPM)tŗ}|i:JFUPRۄJB{}ib[?27ҭ5¡\::|}si-".M; #AwywVCĨ2ѱge)ɔ%oyoow|bc!o?Sw