(√x-3)^2+√x^2-4x+4化简
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/29 20:01:34
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xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1
[x^2+2x-8/x^3+2x^2+x]÷[(x-2/x)×(x+4/x+1)]化简[x^2+2x-8/x^3+2x^2+x]÷[(x-2/x)×(x+4/x+1)]化简
化简:x-2x+3x-4x+5x-.+2011x-2002x
化简:X-2X+3X-4X+5X-……+2001x-2002x
化简 [3x/(x+2)-x/(x=2)]÷x/(x^2-4)化简 [3x/(x+2)-x/(x-2)]÷x/(x^2-4
3x/(x-2)-x/(x+2)÷2x/(x-4)化简3x/(x-2)-x/(x+2)÷2x/(x²-4)化简
化简:(x-1)(x+2)(x-3)(x+4)+24
化简 (x+1)(x+2)(x+3)(x+4)-8
化简:2√(9x)/3+6√(x/4)-2x√(1/x)
化简:2√(9x)/3+6√(x/4)-2x√(1/x)
化简[√(2x-7)]`2-2√(4-4x+x`2)+|x-3|
(6√x/4-2x√1/x)÷3√x 化简
x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4
解方程4x^2+2x√(3x^+x)+x-9=0
(x+3x+5x...+2009x)-(2x+4x+6x+...+2010x)
已知1/√(x)+√(x)=√5,求√(x/x2+x+1)+√(x/x2-x+1)的值定义域 x>0,两边平方,x+2+1/x=5,x+1/x=3,x^2-3x+1=0,x^2+x+1-4x=0,x^2+x+1=4x,x^2-x+1-2x=0.x^2-x+1=2x,√[x/(x^2+x+1)]-√[x/(x^2-x+1)]=√[x/(4x)]-√[x/2x]=√(1/4)-√(1/2)
化简:1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)