设x-10xy+25y+2x-10y+1=0,求x-5y=0的值
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设x-10xy+25y+2x-10y+1=0,求x-5y=0的值
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化简:xy+5x/y^2+10y+25
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x+(9-8-y)=10 y+y-(9-8-y)=2 x-y=xx-9.9x xy=11y-1 y=? x=? x+y-xy=?x+(9-8-y)=10y+y-(9-8-y)=2x-y=xx-9.9xxy=11y-1 y=?x=?x+y-xy=?
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