lg2·lg2+lg2·lg5+lg5是得1吗?怎么得出来的?
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lg5+lg5*lg2+lg2*lg2
lg2·lg2+lg2·lg5+lg5是得1吗?怎么得出来的?
lg2*lg2+lg5-lg2=?
(lg2)^3+3lg2·lg5+(lg5)^3 怎么算?
(lg2)^3+3lg2·lg5+(lg5)^3 怎么算?
lg5·lg20+(lg2)^2
计算(lg2)²+2lg2·lg5+(lg5)²+lg50-lg5求答案,
lg5·lg20+lg2·lg2怎么算?
计算:(lg5)^2+lg2·lg25+(lg2)^2
lg2*lg2+lg20*lg5=?
lg2(lg5-lg2)-lg5(lg5+3lg2)等于
化简lg5的平方+lg5×lg2+lg2
(lg2)^3+(lg5)^3+3*lg2*lg5
(lg2)³+(lg5)³+3lg2×lg5
lg2*lg50+lg5*lg20-2lg5*lg2
2lg2(lg2+lg5)+2lg5得数
(lg5)²+lg2×lg5+lg2
(lg2)^2+lg2*lg5+(lg5)^2=