已知函数f(x)=x²+x-1,α,β是方程f(x)=0的两个根(α>β)f'(x)是f(x)的导数,设a1=1,an+1=an-f(aan+1=an-f(an)÷f"(an)(n=1.2.3...)(1)求α,β的值(2)证明任意的正整数n都有an>α(3)记bn=ln(an-β)/(an-
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