求sin(―1200°)·cos1290°+cos(―1020°)·sin(―1050°)+tan945°的值．

求sin(―1200°)·cos1290°+cos(―1020°)·sin(―1050°)+tan945°的值． 求sin(-1200°）×cos1290°+cos9-1020°)×sin（-1500°）+tan945° 求sin(-1200°）×cos1290°+cos9-1020°)×sin（-1500°）+tan95° 求sin﹙-1200°﹚·cos1290+cos﹙-1020°﹚·sin﹙-1050°﹚+tan945°的值 求sin(-1200°)×cos1290°+cos(-1020°)×sin(-1050°)的值求解求解吖~~~~ sin(-1200°)-cos1290°+cos(-120)°+cos(-1020)°-sin(-1050°)+tan855° sin(-1200°)cos1290°+cos(-1020°）sin（-1050°)+tan855求值.. 求音乐：sin( 1200度)cos1290度 cos( 1020度)in( 1050度)+tan495度 sin(-330°)怎么求? 求sin²10°+sin²20°+sin²40°+sin²50°+sin²70°+sin²80° 求sin平方10°+sin平方20°+.+sin平方80°的值 sin(π-α)=-2sin(π/2+α),求sinα·cosα 求sin²1°+sin²2°+sin²3°……sin²89°=? 求sin（-1050°）三角函数值 sin(-390°)求三角函数值 求值：sin(-1920°)=求过程 sin(-210°)求详细步骤 求大神求sin