lim n[e2-(1+1/n)^2n],当n趋向于无穷答案等于e^2
来源:学生作业帮助网 编辑:作业帮 时间:2024/12/02 07:52:27
xUN@8TTHKC%B/\`hRҤ
Iȿ9u\'J3x:1?;⥀i]5YSd(wȿjq8M=`,s'Pg^D}DI_,s2F:"]3WrV'\2!od'P`S4UD&oUp'7So?oU2u)-䬀=ƭ@Q!L=6w(
\kC3r۟-` S@+h_B-)W6pCT+Ԕ!MvUQ;5hBN cGE!4'%>UR2g$yjjod
b Rz^Iv'Qc A(6Ư矡`lC6ڃTBv6ݫi,1ʀ*UhڍȘުW"-vJsHX0P,Ԫ@ns
ߣ4FPap>a|
ӦliEm8MJ!kPf&`r0N1xUȄ`۵Itࠅsn~/[`eaC\yƂl"mD6ȡY2ءH'#/^o}hߌ7
9ڤRe=2eݙemm9.ۅ.ƛ(~ߔ/O v4
lim n[e2-(1+1/n)^2n],当n趋向于无穷答案等于e^2
lim(n+3)(4-n)/(n-1)(3-2n)
lim[(n+3)/(n+1))]^(n-2) 【n无穷大】
lim(2^n+3^n)^1
(n趋向无穷)
lim(n^3+n)/(n^4-3n^2+1)
lim(1-1/n)^(n^2)=?
lim(1-1/n^2)^n=?
lim(n/n+1)^n 等于多少?
lim (n!+(n-1)!+(n-2)!+(N-3)!+⋯..+2!+1)/n!其中n→∞
lim(n→∞) ((2n!/n!*n)^1/n的极限用定积分求是lim(n→∞) 1/n(2n!/n!)^1/n 不好意思
lim n->无穷大(2^n-1)/(3^n+1)
lim (1+1/2n)^n n趋向于无穷大
lim n->∞{2/((1+ 1/n )^n)}=?
lim(1+1/(n+2))^n其中n趋近无穷
lim根号n^2+n+1/3n-2
lim根号n^2+n+1/3n-2=?
lim (2n-1)/(2^n)=?n=>无穷大
求极限n~∞,lim(n+1)/2n