[(1-log6 3)^2+log6 2·log6 18]·log4 6倒数第二步怎么来的?
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[(1-log6 3)^2+log6 2-log6 18]/log6 4
(log6 2)^2+log6 3*log6 12
(log6^2)^2+(log6^3)*(log6^4)+(log6^3)^2
(log6 3)^2+log6 2+log6 2log6 3=?
{(1-log6 3)^2+log6 2*log6 18}/log6 4 等于多少,请写出就算过程,
((1-log6(3))²+log6(2)*log6(18))/log6(4)
[(1-log6 3)²+log6 2×log6 18]/log6 4
(log6^4)(log6^18)+2(log6^3)^2
(log6 3)^2+log6 18乘以log6 2急求!!!!!!!!!!!!!!
求值:log6^3+log6^2=log6^6为什么?
2^log4(2-根号3)^2+3^log(2+根号3)^2[(1-log6(3)^2+log6(2)*log6(18)]/log6(4)[(1-log6(3))^2+log6(2)*log6(18)]/log6(4)
log6 2=a log6 3=?
[(1-log6底3)^2+log6底2*log6底18]÷log6底4=
化简1/2log6^12–2log6^√2 结果为log6^√3
化简1/2log6^12–2log6^√2 结果为log6^√3 快..
1.log6(1/12)-2log6(3)+1/3log6(27)=
化简[(1-log6^3)^2+logb^2×log6^18]÷log6^4如题
(log6(2))^2+log6(2)*log6(3)+log6(18)的值