(4m+2n)(2m+4n)点解会得出4(2m+n)(m+2n)为什么会提4出来呢,
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(4m+2n)(2m+4n)点解会得出4(2m+n)(m+2n)为什么会提4出来呢,
[(m+n)(m-n)-(m-n)²+2n(m-n)]÷4n
因式分解4m^2(m-n)+4n(n-m)
4m(m-n)^2+4n(n-m)^3
(n/m+n/2m^2)*4m/n^2
[(m-n)^2*(m-n)^3]^2/(m-n)^4
[(m-n)^2*(m-n)^3]^2/(m-n)^4
4m^2(m+n)-9n^2(m+n)
(m-n)2(n-m)3(n-m)4化简
(m-n)^2*(m-n)^4=?
化简,1.[(m+n-p)(m+p+n)-(m+n)²]/(-p),2.[(m+n)(m-n)-(m-n)²+2n(m-n)]/4n
4m(m-m)-2n(n-m)
已知3m=4n,则m/m+n+n/m-n-m^2/m^2-n^2=
(m-2n)(2n+m)-(-3m-4n)(4n-3m)=
(3m-4n)(4n+3m)-(2m-n)(2m+n)
[2(m+n)^5-3(m+n)^4+(-m-n)^3]÷[2(m+n)^3]
计算(m+4n)(m-n)-6(m+2n)(m-3n)
(m+4n)(m-n)-6(m+2n)(m-3n)