√x+5 - √2x-7 = 2

求极限 F(x)=(5x-7)/(2x+√x) x趋于无穷 xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1 *-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少? 填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x (x+12)(x-2)+(x+7)(x+8)-(x+5)(x-10),其中x=2 2x+3x+4x+5x+x+6x+7x=100 √(5x²+10x+1)+x²+2x=7怎么解. x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7 x=? y=(3x^2-x√x+5√x-9)/√x 求导 x^2+√(2x^2-x-4)=1/2*(x+7) 求x x²+4x-2=0,x²-4x+1=0,(x+√5)(x-√5)=20,x²+6x+5=8x+7,25(2x-1)²-16=0, 解方程√(x^2+x+1)-√(x^2+7x+5)=3x+2 求定义域 (1) f(x)=1/x-5 (2) f(x)=√2x-3+√7-x 已知1/√(x)+√(x)=√5,求√(x/x2+x+1)+√(x/x2-x+1)的值定义域 x>0,两边平方，x+2+1/x=5,x+1/x=3,x^2-3x+1=0,x^2+x+1-4x=0,x^2+x+1=4x,x^2-x+1-2x=0.x^2-x+1=2x,√[x/(x^2+x+1)]-√[x/(x^2-x+1)]=√[x/(4x)]-√[x/2x]=√（1/4）-√（1/2） 代数式 当x=√2时 求X^2+7X+4/X^3-X^2-6X + X^2+6X+5/X^2-2X-3 的值 因式分解 x=√2时 求X^2+7X+4/X^3-X^2-6X + X^2+6X+5/X^2-2X-3 的值 已知x=√2-1,求x^5-2x^3+6x^2-7x+2的值