二元一次方程公式法是如何推导出来的 ax²+bx+c  =x²+bx/a+c/a  =x^2+bx/a+(b/2a)²-(b/2a)²+c/a  =(x+b/2a)²-b²/4a²+c/a=0  (x+b/2a)²=b²/4a平方-c/a  (x+b/2a)²=(b^2-4ac)/4

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