(1)|x-2y+1|+|2x-y-5|=0 (2)把x^3-4x分解因式,结果为_____(1)|x-2y+1|+|2x-y-5|=0,则x+y的值为
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分式的加减:[(x/y-y/x)除以(x+y)+x(1/y-1/x)]除以1+x/y,其中x=5,y=2
[(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y
(x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5)
{6(x-y)-7(x+y)=21 {2(x-y)-5(x+y)=-1
-(5x+y)-7(x-y) -2分之1(x+y)+4分之1(x+2y) 4x-2(x-2) -2x-(3x-1) x-(5x-2y)+2(2x-y)
{(x+y)/2+(x-y)/3=1,(x+y)-5(x-y)=2.求x=?,y=?
10/x+y+3/x-y=-5 15/x+y-2/x-y=-1(用换元法解此方程组)
x²-y²+5x+3y+4(x+y-2xy)(x+y-z)+(xy-1)²
计算:1/(2x) - 1/(x+y)((x+y)/(2x) - x - y)
化简1/2x-1/x+y(x+y/2x-x-y)
计算2x/1-x+y/1·(2x/x+y-x-y)
1/2x-(x+y/2x -x-y)÷(x+y)
若(5x+y)/(7x+10y)=1/2则x/y=
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
1、y-x/x²-y²2、(x-y)(y-z)(z-x)/(z-y)(y-x)(x-z)
对于(y一撇)y`=y/x(y-1)求导,我求的结果是y``=-y^2-y`x+y/x^2(y-1)^2 怎么不对啊,我的求导过程是:y`x(y-1) - [x(y-1)]` y y`xy-y`x-(y-1+xy`)y -y^2-y`x+yy``=-------------------------=----------------------=-----------------x^2 (y-1
计算:(1)8x^2y^2*(-3x/4y^5) (2)(x+y)^2/xy-y^2*(y-x)^2/xy+y^2
绝对值化简|x-y+1|-2|y-x-3|+|y-x|+5y