数列{An}满足A1=1,A(n+1)=根号An+An+1/4 (n(-N),求该数列的通项公式不用列举找规律的办法,这类求通项公式的题该怎么做?要过程,谢谢.补一道极限的:lim[(n^3+2n+1)/(n^2+3)-an-b]=0,求a,b.(有没有常规思路啊

已知数列{an}满足a(n+1)=an+n,a1=1,则an= 数列{an}满足a1=2,a(n+1)=2an+n+2,求an 数列an满足a1=1,a(n+1)=an/[(2an)+1],求a2010 已知数列{an}满足a(n+1)=an+lg2,a1=1,求an 数列[An]满足a1=2,a（n+1）=3an-2 求an 数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an 数列{an}满足a1=2,a(n+1)=-1/(an+1),则a2010等于 数列｛an｝满足a1=3,a n+1=2an,则a4等于 已知数列{an}满足a1=1,3a(n+1)+an-7 已知数列an满足a1=1,a(n+1)=an/(3an+1) 求数列通项公式 数列{an)满足an=4a(n-1)+3,a1=0,求数列{an}的通项公式 数列｛an｝满足a1=1,an=a(n-1)+1/(n2-n),求数列的通项公式 已知数列an满足:a1=1,an-a(n-1)=n n大于等于2 求an 已知数列{an}满足a1=33,a(n+1)-an=2n,则an/n的最小值 已知数列{an}满足a1=33,a（n+1）-an=2n,求an/n的最小值 已知数列an满足a1=100,a(n+1)-an=2n,则(an)/n的最小值为 已知数列an满足a1=2,an=a(n-1)+2n,（n≥2）,求an 数列{an}满足a1=1 an+1=2n+1an/an+2n