数列{an}满足a1=1,an+1=根号(an^2+2)(n属于N*),则该数列的通项公式an=
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/13 20:37:32
x){6uӎՉyv/|msNb;oH̋36{qޓ]}~Z:O;fX
^.u=y6IE0VΆf gd{n_RX MY$ g34O@T&B哌m`a1Nn_lN Ox
O7YI7<q AcHD*656E$فB hK
已知数列an满足a1=1,1/an+1=根号1/an^2+2,an>0,求an
数列an满足an+1=根号(an^2+1)+an,a1=a>0,求an通项公式
已知数列an满足a1=0,an+1=an-根号3/根号3an+1,则a2012=
已知数列满足a1=1,根号an-1-根号an=根号anan-1,求an
数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an
已知数列{an}满足a1=1 an+1=an/(3an+1) 则球an
已知数列{an}满足a1=0,an+1=(an-根号3)/(根号3an+1) (n属于N+),则该数列中a20=____
已知数列{an}满足a1=1,1/an+1=根号1/an62+2,an>0,求an是根号【1/(an^2+2)]
数列{an}满足a1=1,an+1*根号(1/an^2+4)=1,S2n+1-Sn
已知数列{an}满足,a1=2,a(n+1)=3根号an,求通项an数列{an}满足:an>0,且根号下Sn=an+1/4,求通项an
数列{an}满足a1=1 an+1=2n+1an/an+2n
已知数列{an}满足an+1=an+n,a1等于1,则an=?
数列{an}满足a1=1,且an=an-1+3n-2,求an
数列an满足a1=2,an+1=4an+9,则an=?
已知数列{an}满足an+1=2an+3.5^n,a1=6.求an
数列an满足a1=2,an+1=an²求an
数列an满足a1=2,an+1=an²求an
数列[An]满足An+1-An+3=0,且A1=-5.求An.