已知函数f(x)=sin(π/3+wx)+cos(wx-π/6)(w>0)f(x)的最小正周期为π求f(x)解析式以及单调区间不要用和差化积公式积化和差.我们还没学来
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[非常急]已知函数f(x)=根号3sin(wx+φ)-cos(wx+φ)(0
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已知函数f(x)=sin wx-cos wx最小周期为π 求w 若f(a/2)=1/3求sin2a的值