用换元法求 ( X/(X-1) )^2-5(X/ (X-1) )^2+6=0 3X/(X^2-1)+(X^2-1)/3X=2/5( X/(X-1) )^2-5(X/ (X-1) )^2+6=0 3X/(X^2-1)+(X^2-1)/3X=2/5
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1/(1-x)+1/(1+x)+2/(1+x*x)+4/(1+x*x*x*x)+8/(1-x*x*x*x*x*x*x*x)怎么做
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