求24xy^2z^2(x+y-z)-32xyz(z-x-y)^2+8xyz^3(z-x-y)怎么做!明天要交嗯,七年级数学练习册28页第8题,24xy^2z^2(x+y-z)-32xyz(z-x-y)^2+8xyz^3(z-x-y),

24xy^2z^2(x+y+z)-32xyz(z-x-y)^2+8xyz^3(z-x-y) 24xy^2z^2(x+y+z)-32xyz(z-x-y)^2+8xyz^3(z-x-y) 求24xy^2z^2(x+y-z)-32xyz(z-x-y)^2+8xyz^3(z-x-y)怎么做!明天要交嗯,七年级数学练习册28页第8题,24xy^2z^2(x+y-z)-32xyz(z-x-y)^2+8xyz^3(z-x-y), xz+xy^2=e^z 求&z/&x ,&z/&y 设函数z=z(x,y)由方程e^(-xy)-2z+e^z=0确定,求z/x,z/y 已知XY=2(X+Y),YZ=4(Y+Z),ZX=5(Z+X),求X,Y,Z已知XY=2(X+Y),YZ=4(Y+Z),ZX=5(Z+X),求X,Y,Z 24xy^2*z^2(x+y-z)-32xyz(z-x-y)^2+8xyz^3(z-x-y） 方程组xy/x+y=2 yz/y+z=4 zx/x+z=5 求x,y,z 已知实数x,y,z,满足那么x+y=6,z^2=xy-9,求(x+y)^z 化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+（z-y)(x-y)/(xy-2z)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)速速回答 设z=f(xy^2-x^2y)求z对xy的二阶偏导 若x+y=6,xy=-8,求代数式(x+y-z)^2+(x+y-z)(x+y+z)-2·z(x-y) 若x-y=6,xy=-8,求代数式(x+y+z)²+(x-y-z)(x-y+z)-2·z(x+y)的值 若x,y,z满足x2+2y2+z2≤2xy-2y+4Z,求x,y,z 若|x-3|+|y+2|+|2z+1|=0,求(xy-yz)(y-x+z) 已知方程组x+2y-z=0,2x-y+8z=0,求x*x+y*y+z*z/xy+yz的值 求(2X+Z-Y)/(X^2-XY+XZ-YZ)-(2X+Y+Z)/(X^2+XY+XZ+YZ) z=f(x^2-y^2,xy),求z关于y的偏导