证明sin^2atan^2a=tan^2a-sin^2a

证明sin^2atan^2a=tan^2a-sin^2a 证明cos^2a+2sin^2a+sin^2atan^2a=1/cos^2a 证明：tan^2a-sin^2a=tan^2*sin^2a 证明tan a/2=sin a/(1+cos a) 已知tan(a+b)=2tan a 证明 3sinb=sin(2a+b) 已知sin(A+B)=3/5,sin(A-B)=1/5,证明：tan A=2tan B. 证明(tan^2-sin^2)cot^2=sin^2 证明：(1+tan a+cot a)/(1+tan^2 a+tan a)-cot a/(1+ tan^2 a)=sin a*cos a 怎样用matlab解方程组?x1+x01=sqrt(x2^2+y2^2)*cos(a+atan(y2/x2))+qrt(x01^2+y01^2)*cos(a+atan(y01/x01))；y1+y01=sqrt(x2^2+y2^2)*sin(a+atan(y2/x2))+y02=sqrt(x01^2+y01^2)*sin(a+atan(y01/x01))其中x1,y1,x2,y2是已知量,要求x01,y01. 证明:cos^4 a-sin^4 a=cos^2 a(1-tan a)(1+ tan a) 证明:（1）2sin(兀+a)*cosa-1/1-2sin^2a=tan(9兀+a)-1/tan(兀+a)+1 证明:(2)tan(2兀-a)*sin(-2兀-a)*cos(6证明:（1）2sin(兀+a)*cosa-1/1-2sin^2a=tan(9兀+a)-1/tan(兀+a)+1证明:(2)tan(2兀-a)*sin(-2兀-a)*cos(6兀-a)/cos(a-兀)*sin(5兀+a)=t 证明(2-cos^2a)(2+tan^2a)=(1+2tan^2a)(2-sin^2a) 证明(2-cos^2a)(2+tan^2a)=(1+2tan^2a)(2-sin^2a) matlab中 如何求a=atan((2*sin(x))/(2*cos(x) + 1))的反函数呢,该方程由tan(a)+2*tan(a)*cos(x)=2*sin(x)化简求出,我已经知道a的取值范围是0~30度,但是直接求反函数的话是没有显式解的,得出的是虚数解,应该是 tan a/2=(1-cos a)/sin a=sin a/(1+cos a)如何证明? 证明tan^2x-sin^2x=tan^2 sin^2x 证明:(tan^2)x-(sin^2)x=(tan^2)x(sin^2)x 证明：tan^2角-sin^2角=tan^2角sin^2角