2x²+y²+2xy-2y+2=0 求x+y=( )
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x²-2xy+y²-9
因式分解2x²+4xy+2y²-8z²
已知X+Y=12,XY=9.求(X²+3XY+2Y²)÷(X²Y+2XY²)
若x²+xy-2y²=0,则x²+3xy+y²/x²+y²
x²+xy-2y²=0则x²+3xy+y²/x²+y²
设x²+xy=3,xy+y²=2,求2x²-xy-3y²的值
因式分解 x²-2xy+y²-z²
计算:4xy²-3x²y-{3x²y-[2xy²-4x²y+2(x²y-2xy²)]急
x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy
已知3y²-2y+6=8,求3/2y²-y+1的值2.已知(x²+y²)(x²+y²-1)=12,求x²+y²的值3.若xy≠0且,x²-5xy+6y²=0求x/y的值
计算x²-x/x²×x/1-x和x²-4y²/x²+2xy+y²÷x+2y/x²+xy
3y/2x+2y+2xy/x²+xy 2x/x²-64y²-1/x-8y (1/a+1/b)²÷(1/a²-1/b²) (3x&su3y/2x+2y+2xy/x²+xy 2x/x²-64y²-1/x-8y (1/a+1/b)²÷(1/a²-1/b²) (3x²/4y)²×2y/3x+x²/2y²÷2y²/
x²-y²+6x+9分之x²+y²-9-2xy
3x²-y²=8x²+xy+y²=4
因式分解 x²-XY-2y²-X-Y
x²+xy-2y²-x+7y-6
分解因式:x²-3xy+2y²+x-2
(xy-x²)÷[(x²-2xy+y²)÷xy]*[(x-y)÷x²]