方程组{-2x+y=3 4x-2y=-6的解是什么?两个方程对应两个一次函数有怎样的位置方程组{-2x+y=3 4x-2y=-6的解是什么?两个方程对应两个一次函数有怎样的位置关系?你能从中悟出些什么?

解方程组,x+y/2=3x-2y=10+6x+y/4, 解方程组2(x-y)/3-x+y/4=-1 6(x-y)-4(2x-y)=16 解方程组：2(x-y)/3-x+y/4=-1 ,6(x+y)-4(2x-y)=16 2元一次方程组 2/x+y+3/x-y=6 4(x+y)-3(x-y)=-20 解方程组;x+y/2=x-y/3=6 4(x+y)-3(x-y)=-20 解方程组 X+Y/2+X-Y/3=6 4[X+Y]-5[X-Y]=2 解二元一次方程组{x+y/2+x-y/3=6,4(x+y)-2=5(x-y) 解方程组2分之x+y+3分之x-y=6 4(x+y)-5(x-y)=2 解方程组 {(x+y)/2+(x-y)/3=6 5(x+y)-2(x-y)=4 x+y/2+x-y/3=6,4(x+y)-5(x-y)=2用加减消元法解方程组 解二元一次方程组3(x+y)-4(x-y)=4 x+y/2+x-y/6=1 解方程组3(x+y)-4(x-y)=4和(x+y)/2+(x-y)/6=1kkkkkkkk 3(x+y)—4(x-y)=4,(x+y/2)+(x-y/6)=1.解方程组 解方程组3(x+y)-4(x-y)=4,x+y除以2+x-y除以6=1 一道二元一次方程组!3(x+y)-4(x-y)=4,(x+y)/2+(x-y)/6=1 解方程组⑴(x+y)/2-(x-y)/3=6,⑵3(x+y)=4(x-y) 解方程组 x-y/3-x+y/4=2 x-y/6-x+y/8=3 解方程组4（x+y)-3(x-y)=14;(x+y)/2+(x+y)/3=6