设A={x|2x^2+ax+2=0} B={x|x^2+3x+2a=0} 且A交B={2}求a的值 集合A B

设集合A={x/x^2-3x-4>0},B={x/x^2-ax+b 设f(x)=x^2+ax+b,且0 线性代数2,设AX+B=X 设集合A={x|2x^2-ax+b=0},B={x|x^2+6x+8,x∈R},求A∩B 设lim(x->无穷大)((1+x^2+x^3)^1/3-ax-b)=0,求a= ,b= . 设lim（(x^2+1)/(x+1) -ax-b）=0,求a,b.x趋向无穷大 设lim（(x^2+1)/(x+1) -ax-b）=0,求a,b. x趋向无穷大 设不等式x^2-ax-8>=0与x^2-2ax-b 设lim[(x^2+2x+3)^1/2-ax]=b,求a,b f(x)=Inx-ax^2+2x-ax 设a>0 证明 当0 设集合A={x|x^2-2ax+3 设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0 设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0 设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0 设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0 设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0 设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0 设集合A={x|log1/2(6+x-x^2)>-2},B={x|根号下ax-a^2|