若x²-xy-6y²=o (xy≠0）则x∶y的值为多少

-9x²-y²+6xy 6xy²-9x²y-y²因式分解 若x²+xy-2y²=0,则x²+3xy+y²/x²+y² 若|x+y-5|+(xy-6)²=0,求x²+y²的值. x²-y²+6x+9分之x²+y²-9-2xy x²+xy-2y²-x+7y-6 若(x+y-5)²+(xy-6)²=0,则（x+y)²-2xy的值为? 6x²-xy-15y²=0 求x²-2xy+4y²/2x²-3xy-3y²告诉下 6x²-xy-15y²=0 求2x²-3xy-3y²分之x²-2xy+4y² 6xy²-9x²y-y³ 6xy²-9x²y-y³因式分解 6x²y-9xy-xy²+3x²y 3x³ - 6x²y+ 3xy² 若x/y=2,求分式(x²-xy+3y²)/(x²+xy+6y²)的值 若x² +xy+y² =14,x² -xy+y²=28求x+y的值 若x²+xy+y²=14,x²-xy+y²=28,求x+y的值 x/y=2,求分式x²-xy+3y²/x²+xy+6y² 1.y²-5xy-6x² 2.m²-3mn+2n²