已知x^2+2xy+y^2-10y+26=0,求(1)x+2y的平方根 (2)2y+2x的立方根
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已知x-xy=10,xy-y=2,则x-y=( ),-2xy+x+y=( ).
已知x-xy=20,xy-y=-10,则x-y=( ),x+y-2xy=( ).
已知x-xy=20,xy-y=-10,则x-y=?x+y-2xy=?
已知x-xy=20,xy-y=-10,则x-y=?,x+y-2xy?
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