满足 (a-b)^2+(b-a) \a-b\ =ab ,(ab不等于0)的有理数a,b一定不满足的关系是：注：（\a-b\ 是 a-b 的绝对值!）A.ab0C.a+b>0D.a+b

a,b满足0 a,b满足0 如果有理数a,b满足a+b 有理数a,b满足a>0,b 若实数a,b满足a+b 有理数a,b满足a>0,b 有理数a、b满足：a>0,b 有理数A.B满足A.>0,b 有理数ab满足a+b＜0.化简|a+b|+(-a)+(-b)+2a+2b 已知实数a,b满足a>b,求证：-a^2-a＜-b^3-b 若非零向量a,b满足/a+b/=/b/,证明/2b/>/a+2b/ 若平面向量a,b满足|2a-b| 已知向量a,b满足（a+2b）… 若实数a,b,c满足a^2+a+bi 已知a,b满足条件/a-b/=b/a 若非零向量a,b满足/a+b/=/b/,则若非零向量a.b满足|a+b|=|b|,则 A.|2a|>|2a+b| B.|2a||a+2b| D.|2b| 若角A,B满足-π/2 若角A、B满足-π/2