tana=-1/3 (2sin^a+sin2a)/cos(a-π/4）=?-π/2

tana/2+tana/2=5/2,求sin(a-pai/3)1 tanA=2 求(sin^2 A+ sinAcosA)/(tanA+1+sin^2 A) 急 . 求证sin^2a*tana+cos^2a*1/tana+2sina*cosa=tana+1/tana sin(a+b)=1/2,sin(a-b)=1/3,则tana/tanb=? sin(a+b)=1/2,sin(a-b)=1/3,则tana/tanb=? 已知sin(a+b)=1/2,sin（a-b)=1/3,求tana/tanb 已知sin(a+x)=1/2,sin(a-x)=1/3,则tana/tanx 已知sin(A+B)=2/3,sin(A-B)=1/5.求tanA/tanB 已知sin(a+b)等于2/3,sin(a-b0 =1/5,求tana:tanb sin^2A+cos^2A/sinAcosA=-10/3怎么得到 tanA+1/tanA=-10/3 (1+tanA )/1-tanA=3+根2 求cos平方(pai-A)+sin(pai+A)*cos(pai-A)+2sin平方（A-3pai) 已知(1+tana)/(1-tana)=3+2√2,求cos(π-a)方+sin(π+a)cos(π-a)+sin(a-π)方 [3sin^2 (a/2)-2sin(a/2)cos(a/2)+cos^2 (a/2)]/[tana+1/tana] tanA=1/ tanA=sinA/ cotA=cosA/ sin^2A+cos^2A= 求证1+2sina cosa/sin^2a-cos^2a=tana+1/tana-1 (1-2sinAcosA)/(cos^2A-sin^2A)=(1-tanA)/(1+tanA) 证明(1-2sinAcosA)/(cos^2A-sin^2A)=(1-tanA)/(1+tanA) 求证：(1-tana)/(1+tana)=(1-2sinacosa)/(cos^2×a-sin^2×a)