2012贵州先化简1/x+1-3-x/x2-6x+91/(x+1)-[(3-x)/(x^2-6x+9)]÷[(x^2+x)/(x-3)]=1/(x+1)+[(x-3)/(x-3)^2][(x-3)/(x^2+x)]=1/(x+1)+1/(x^2+x)=1/(x+1
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