数列﹛an﹜满足a1=1,1/2a(n+1)=1/2an+1(n∈N*)数列an满足a1=1 1/2a(n+1)=1/2an+1(n∈N*)1.求证数列1/an是等差数列2 设Tn=a1a2+a2a3+...+anan+1,若Tn≧a恒成立,求a的取值范围
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